X^2+7x+49=484

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Solution for X^2+7x+49=484 equation: 



X^2+7X+49=484

We move all terms to the left:

X^2+7X+49-(484)=0

We add all the numbers together, and all the variables

X^2+7X-435=0

a = 1; b = 7; c = -435;
Δ = b2-4ac
Δ = 72-4·1·(-435)
Δ = 1789
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1789}}{2*1}=\frac{-7-\sqrt{1789}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1789}}{2*1}=\frac{-7+\sqrt{1789}}{2}
$

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